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Popular >

y^'=-x(y+1)

Solution

y^{^{'}} = - x (y + 1)

Solution

y = e^{- \frac{x ^{2}}{2} + c_{1}} - 1

Solution steps

y^{'} (x) = - x (y + 1)

Solve separable ODE:

y = e^{- \frac{x ^{2}}{2} + c_{1}} - 1

y = e^{- \frac{x ^{2}}{2} + c_{1}} - 1

Graph

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\frac{d}{d K} ((K^{a} L^{0.5})^{Y (K)})

(d^3)/(dx^3)(sqrt(6t+8))

\frac{d ^{3}}{d x ^{3}} (6 t + 8)

Frequently Asked Questions (FAQ)

What is the solution for y^'=-x(y+1) ?
The solution for y^'=-x(y+1) is y=e^{-(x^2)/2+c_{1}}-1