What is the integral of e^{-0.6x} ?

The integral of e^{-0.6x} is -1.66666…e^{-0.6x}+C

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integral of e^{-0.6x}

\int e^{- 0.6 x} d x

- 1.66666 \dots e^{- 0.6 x} + C

Solution steps

\int e^{- 0.6 x} d x

Apply u-substitution

: \int - \frac{1}{0.6} e^{u} d u

= \int - \frac{1}{0.6} e^{u} d u

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= - \frac{1}{0.6} \cdot \int e^{u} d u

Simplify

= - 1.66666 \dots \cdot \int e^{u} d u

Use the common integral:

\int e^{u} d u = e^{u}

= - 1.66666 \dots e^{u}

Substitute back

u = - 0.6 x

= - 1.66666 \dots e^{- 0.6 x}

Add a constant to the solution

= - 1.66666 \dots e^{- 0.6 x} + C

y = 9 x^{2} + 3 x - 9

- \frac{y ^{2}}{t ^{2}} d t + \frac{2 y}{t} d y = 0

x \to - 3 lim (- h (x))

(5 x^{6} + 4 x^{3})^{4}

\frac{d}{d x} (\frac{1 - x}{1 + x})

What is the integral of e^{-0.6x} ?
The integral of e^{-0.6x} is -1.66666…e^{-0.6x}+C