What is the tangent of f(x)=3x^2-5x,(2,2) ?

The tangent of f(x)=3x^2-5x,(2,2) is y=7x-12

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tangent of f(x)=3x^2-5x,(2,2)

tangent of

f (x) = 3 x^{2} - 5 x, (2, 2)

y = 7 x - 12

Solution steps

Find the slope of

f (x) = 3 x^{2} - 5 x : \frac{df ( x )}{d x} = 6 x - 5

EN : T i tl e G e n er a l Eq u a t i o n Sl o p e A t P o in t 2 Eq : m = 7

Find the line with slope m=

7

and passing through

(2, 2) : y = 7 x - 12

y = 7 x - 12

\int \frac{sec ( x ) + cos ( x )}{9 cos ( x )} d x

3 x^{4} + 2 x^{3} + x^{2} - 2

(x^{2} - 1) y^{^{'}} = x y

\int x sin (6 x) d x

y = 3 x, y = 2 x^{2}

What is the tangent of f(x)=3x^2-5x,(2,2) ?
The tangent of f(x)=3x^2-5x,(2,2) is y=7x-12