en

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

y^'=-(4t)/y ,y(0)=2

Solution

y^{^{'}} = - \frac{4 t}{y}, y (0) = 2

Solution

y = 2 - t^{2} + 1

Solution steps

y^{'} (t) = - \frac{4 t}{y}

Solve separable ODE:

y = 2 - t^{2} + 1

y = 2 - t^{2} + 1

Graph

Popular Examples

(\partial)/(\partial x)(((x+1))/(x^2))

\frac{\partial}{\partial x} (\frac{( x + 1 )}{x ^{2}})

(\partial)/(\partial x)(2/(x^2+y^2+z^2))

\frac{\partial}{\partial x} (\frac{2}{x ^{2} + y ^{2} + z ^{2}})

integral of 20x(5x^2-3)^3

\int 20 x (5 x^{2} - 3)^{3} d x

integral of (sin^2(x))^2

\int (sin^{2} (x))^{2} d x

(d^2y)/(dx^2)+4y=0

\frac{d ^{2} y}{d x ^{2}} + 4 y = 0

Frequently Asked Questions (FAQ)

What is the solution for y^'=-(4t)/y ,y(0)=2 ?
The solution for y^'=-(4t)/y ,y(0)=2 is y=2sqrt(-t^2+1)