What is the derivative of h(x)=log_{9}(x) ?

The derivative of h(x)=log_{9}(x) is 1/(2ln(3)x)

What is the first derivative of h(x)=log_{9}(x) ?

The first derivative of h(x)=log_{9}(x) is 1/(2ln(3)x)

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

derivative of

h (x) = lo g_{9} (x)

\frac{1}{2 ln ( 3 ) x}

Solution steps

\frac{d}{d x} (lo g_{9} (x))

Apply the derivative log rule:

\frac{d}{d x} (lo g_{a} (x)) = \frac{1}{x ln ( a )}

= \frac{1}{x ln ( 9 )}

Simplify

ln (9) : 2 ln (3)

= \frac{1}{2 ln ( 3 ) x}

\frac{d}{d x} (7 cos (x) + 3 e^{x})

y = 1 + cot^{2} (x)

\frac{d}{d x} (e^{2 x} + e^{3 x})

\int \frac{- 2200 x}{25 - x ^{2}} d x

\int \frac{e ^{x}}{e ^{2 x} + 3} d x

What is the derivative of h(x)=log_{9}(x) ?
The derivative of h(x)=log_{9}(x) is 1/(2ln(3)x)
What is the first derivative of h(x)=log_{9}(x) ?
The first derivative of h(x)=log_{9}(x) is 1/(2ln(3)x)