What is area y=sqrt(9-x^2),y=0 ?

The answer to area y=sqrt(9-x^2),y=0 is (9pi)/2

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area y=sqrt(9-x^2),y=0

area

y = 9 - x^{2}, y = 0

\frac{9 π}{2}

Decimal

14.13716 \dots

Solution steps

Apply the area formula:

\int_{- 3}^{3} - x^{2} + 9 d x

Solve

\int_{- 3}^{3} - x^{2} + 9 d x : \frac{9 π}{2}

The area is:

= \frac{9 π}{2}

y = (5 - x^{2}) (x^{3} - 3 x + 2)

\int_{1}^{2} 2 x^{2} d x

y = cos (5 x)

\int_{0}^{\frac{1}{3}} arcsin (3 y) d y

x \to π lim (\frac{3 x + 1}{1 - x})

What is area y=sqrt(9-x^2),y=0 ?
The answer to area y=sqrt(9-x^2),y=0 is (9pi)/2