What is the derivative of f(x)= 9/x ?

The derivative of f(x)= 9/x is -9/(x^2)

What is the first derivative of f(x)= 9/x ?

The first derivative of f(x)= 9/x is -9/(x^2)

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derivative of

f (x) = \frac{9}{x}

- \frac{9}{x ^{2}}

Solution steps

\frac{d}{d x} (\frac{9}{x})

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= 9 \frac{d}{d x} (\frac{1}{x})

Apply exponent rule:

\frac{1}{a} = a^{- 1}

= 9 \frac{d}{d x} (x^{- 1})

Apply the Power Rule:

\frac{d}{d x} (x^{a}) = a \cdot x^{a - 1}

= 9 (- 1 \cdot x^{- 1 - 1})

Simplify

9 (- 1 \cdot x^{- 1 - 1}) : - \frac{9}{x ^{2}}

= - \frac{9}{x ^{2}}

\frac{d}{d x} (\frac{1}{x} + x - \frac{1}{x} - x)

y^{^{'}} = t - y

x cos (x), - \frac{π}{2}, \frac{π}{2}

\frac{\partial}{\partial x} (- cos (x) + x cos (y))

\frac{d}{d x} (x cos (x) cos (y))

What is the derivative of f(x)= 9/x ?
The derivative of f(x)= 9/x is -9/(x^2)
What is the first derivative of f(x)= 9/x ?
The first derivative of f(x)= 9/x is -9/(x^2)