What is (\partial)/(\partial x)(-cos(x)+xcos(y)) ?

The answer to (\partial)/(\partial x)(-cos(x)+xcos(y)) is sin(x)+cos(y)

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(\partial)/(\partial x)(-cos(x)+xcos(y))

\frac{\partial}{\partial x} (- cos (x) + x cos (y))

sin (x) + cos (y)

Solution steps

\frac{\partial}{\partial x} (- cos (x) + x cos (y))

Treat

y

as a constant

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= - \frac{\partial}{\partial x} (cos (x)) + \frac{\partial}{\partial x} (x cos (y))

\frac{\partial}{\partial x} (cos (x)) = - sin (x)

\frac{\partial}{\partial x} (x cos (y)) = cos (y)

= - (- sin (x)) + cos (y)

Simplify

= sin (x) + cos (y)

\frac{d}{d x} (x cos (x) cos (y))

\int e^{\frac{x}{2}} d x

\frac{d}{d x} (7 x^{- 12})

\frac{d}{d x} (4 x^{2} + 2 x)

\int lo g_{10} (x) d x

What is (\partial)/(\partial x)(-cos(x)+xcos(y)) ?
The answer to (\partial)/(\partial x)(-cos(x)+xcos(y)) is sin(x)+cos(y)