What is the limit as t approaches 0 of (4t+2)/(t+1) ?

The limit as t approaches 0 of (4t+2)/(t+1) is 2

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limit as t approaches 0 of (4t+2)/(t+1)

t \to 0 lim (\frac{4 t + 2}{t + 1})

2

Solution steps

t \to 0 lim (\frac{4 t + 2}{t + 1})

Plug in the value

t = 0

= \frac{4 \cdot 0 + 2}{0 + 1}

Simplify

= 2

(19.3) (20.3)

x e^{- x + 1}

\int 0. 5^{x} d x

\frac{d}{d x} (x^{2} + y^{2} - 1)

\frac{d}{d x} (e^{s i n (x)})

What is the limit as t approaches 0 of (4t+2)/(t+1) ?
The limit as t approaches 0 of (4t+2)/(t+1) is 2