What is the solution for (dy)/(dx)=(y^2+xy+x^2)/(x^2) ?

The solution for (dy)/(dx)=(y^2+xy+x^2)/(x^2) is y=tan(ln(x)+c_{1})x

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

(dy)/(dx)=(y^2+xy+x^2)/(x^2)

\frac{d y}{d x} = \frac{y ^{2} + x y + x ^{2}}{x ^{2}}

y = tan (ln (x) + c_{1}) x

Solution steps

\frac{d y}{d x} = \frac{y ^{2} + x y + x ^{2}}{x ^{2}}

Solve using substitution:

y = tan (ln (x) + c_{1}) x

y = tan (ln (x) + c_{1}) x

\int sin^{2} (y) cos (y) d y

\frac{1}{( s - 1 ) ( s + 4 )}

\int (4 x^{3} - 2 x) (x^{4} - x^{2} - 5)^{3} d x

x \to + 0 + lim (arctan (\frac{2}{x}))

\frac{d}{d x} \frac{8}{( x ^{3} + x ^{2} + 1 ) ^{3}}

What is the solution for (dy)/(dx)=(y^2+xy+x^2)/(x^2) ?
The solution for (dy)/(dx)=(y^2+xy+x^2)/(x^2) is y=tan(ln(x)+c_{1})x