What is the derivative of (4x+3^2) ?

The derivative of (4x+3^2) is 8(4x+3)

What is the first derivative of (4x+3^2) ?

The first derivative of (4x+3^2) is 8(4x+3)

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\frac{d}{d x} ((4 x + 3)^{2})

8 (4 x + 3)

Solution steps

\frac{d}{d x} ((4 x + 3)^{2})

Apply the chain rule:

2 (4 x + 3) \frac{d}{d x} (4 x + 3)

= 2 (4 x + 3) \frac{d}{d x} (4 x + 3)

\frac{d}{d x} (4 x + 3) = 4

= 2 (4 x + 3) \cdot 4

Simplify

= 8 (4 x + 3)

(\frac{5 - v ^{2}}{5 + v ^{2}})^{^{'}}

\int_{1}^{2} (\frac{1}{x} - e^{- x}) d x

f (x) = e^{x}, at x = ln (11)

f (x) = 8 x - x^{2}

\frac{\partial}{\partial x} (ln (3 x^{2} + 2 y^{3}))

What is the derivative of (4x+3^2) ?
The derivative of (4x+3^2) is 8(4x+3)
What is the first derivative of (4x+3^2) ?
The first derivative of (4x+3^2) is 8(4x+3)