What is the derivative of f(x)=\sqrt[4]{-3x^4-2} ?

The derivative of f(x)=\sqrt[4]{-3x^4-2} is -(3x^3)/((-3x^4-2)^{3/4)}

What is the first derivative of f(x)=\sqrt[4]{-3x^4-2} ?

The first derivative of f(x)=\sqrt[4]{-3x^4-2} is -(3x^3)/((-3x^4-2)^{3/4)}

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

derivative of

f (x) = 4 - 3 x^{4} - 2

- \frac{3 x ^{3}}{( - 3 x ^{4} - 2 ) ^{\frac{3}{4}}}

Solution steps

\frac{d}{d x} (4 - 3 x^{4} - 2)

Apply the chain rule:

\frac{1}{4 ( - 3 x ^{4} - 2 ) ^{\frac{3}{4}}} \frac{d}{d x} (- 3 x^{4} - 2)

= \frac{1}{4 ( - 3 x ^{4} - 2 ) ^{\frac{3}{4}}} \frac{d}{d x} (- 3 x^{4} - 2)

\frac{d}{d x} (- 3 x^{4} - 2) = - 12 x^{3}

= \frac{1}{4 ( - 3 x ^{4} - 2 ) ^{\frac{3}{4}}} (- 12 x^{3})

Simplify

\frac{1}{4 ( - 3 x ^{4} - 2 ) ^{\frac{3}{4}}} (- 12 x^{3}) : - \frac{3 x ^{3}}{( - 3 x ^{4} - 2 ) ^{\frac{3}{4}}}

= - \frac{3 x ^{3}}{( - 3 x ^{4} - 2 ) ^{\frac{3}{4}}}

4 cos (x) + 12 x

\int_{1}^{2} \frac{5}{x ^{2}} d x

f (x) = 8 x - 3, at x = 64

\frac{d}{d y} (y x^{2})

y^{^{''}} + 11 y^{^{'}} + 22 y = 3468 e^{2 t} cos (12 t)

What is the derivative of f(x)=\sqrt[4]{-3x^4-2} ?
The derivative of f(x)=\sqrt[4]{-3x^4-2} is -(3x^3)/((-3x^4-2)^{3/4)}
What is the first derivative of f(x)=\sqrt[4]{-3x^4-2} ?
The first derivative of f(x)=\sqrt[4]{-3x^4-2} is -(3x^3)/((-3x^4-2)^{3/4)}