What is the integral from 1 to 32 of (x^{-6/5}) ?

The integral from 1 to 32 of (x^{-6/5}) is 5/2

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integral from 1 to 32 of (x^{-6/5})

\int_{1}^{32} (x^{- \frac{6}{5}}) d x

\frac{5}{2}

Decimal

2.5

Solution steps

\int_{1}^{32} x^{- \frac{6}{5}} d x

Apply the Power Rule

: [- \frac{5}{x ^{\frac{1}{5}}}]_{1}^{32}

= [- \frac{5}{x ^{\frac{1}{5}}}]_{1}^{32}

Compute the boundaries:

\frac{5}{2}

= \frac{5}{2}

f (x) = 3 x + 13, (12, 7)

y = 3 (ln (x) + 1)

\frac{d}{d x} (2 cos (5 x))

h \to 0 lim ((1 + \frac{h}{y})^{\frac{1}{h}})

\int (2 + \frac{1}{x})^{2} d x

What is the integral from 1 to 32 of (x^{-6/5}) ?
The integral from 1 to 32 of (x^{-6/5}) is 5/2