What is the sum from n=0 to infinity of 1/(e^{2n)} ?

The sum from n=0 to infinity of 1/(e^{2n)} is converges

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sum from n=0 to infinity of 1/(e^{2n)}

n = 0 \sum \infty \frac{1}{e ^{2 n}}

converges

Solution steps

n = 0 \sum \infty \frac{1}{e ^{2 n}}

Apply Series Ratio Test:

converges

= converges

\int (2 x - 1)^{\frac{1}{2}} d x

\frac{\partial}{\partial x} (- y)

(7 x + 3)^{2}

y^{^{''}} - 4 y^{^{'}} + 3 y = 2 cos (3 t)

f (x) = \frac{2 x - x ^{2}}{4 x ^{2} + 1}

What is the sum from n=0 to infinity of 1/(e^{2n)} ?
The sum from n=0 to infinity of 1/(e^{2n)} is converges