What is the slope of f(x)=(2x-x^2)/(4x^2+1) ?

The slope of f(x)=(2x-x^2)/(4x^2+1) is (-8x^2-2x+2)/((4x^2+1)^2)

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slope of f(x)=(2x-x^2)/(4x^2+1)

slope

f (x) = \frac{2 x - x ^{2}}{4 x ^{2} + 1}

\frac{- 8 x ^{2} - 2 x + 2}{( 4 x ^{2} + 1 ) ^{2}}

Solution steps

f (x) = \frac{2 x - x ^{2}}{4 x ^{2} + 1}

In order to find the slope of the function, take the derivative of

\frac{2 x - x ^{2}}{4 x ^{2} + 1}

\frac{d}{d x} (\frac{2 x - x ^{2}}{4 x ^{2} + 1}) = \frac{- 8 x ^{2} - 2 x + 2}{( 4 x ^{2} + 1 ) ^{2}}

\frac{- 8 x ^{2} - 2 x + 2}{( 4 x ^{2} + 1 ) ^{2}}

\frac{d}{d x} (\frac{4}{7 x ^{3}})

\frac{d}{d x} ((6 x)^{6 x})

y^{^{'}} + y + 3 sin (x) = 0

y = x^{2} - 14, y = 7 - 4 x

\frac{d}{d x} (\frac{1}{x ^{13}})

What is the slope of f(x)=(2x-x^2)/(4x^2+1) ?
The slope of f(x)=(2x-x^2)/(4x^2+1) is (-8x^2-2x+2)/((4x^2+1)^2)