What is the derivative of 4/(7x^3) ?

The derivative of 4/(7x^3) is -(12)/(7x^4)

What is the first derivative of 4/(7x^3) ?

The first derivative of 4/(7x^3) is -(12)/(7x^4)

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\frac{d}{d x} (\frac{4}{7 x ^{3}})

- \frac{12}{7 x ^{4}}

Solution steps

\frac{d}{d x} (\frac{4}{7 x ^{3}})

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= \frac{4}{7} \frac{d}{d x} (\frac{1}{x ^{3}})

Apply exponent rule:

\frac{1}{a} = a^{- 1}

= \frac{4}{7} \frac{d}{d x} (x^{- 3})

Apply the Power Rule:

\frac{d}{d x} (x^{a}) = a \cdot x^{a - 1}

= \frac{4}{7} (- 3 x^{- 3 - 1})

Simplify

\frac{4}{7} (- 3 x^{- 3 - 1}) : - \frac{12}{7 x ^{4}}

= - \frac{12}{7 x ^{4}}

\frac{d}{d x} ((6 x)^{6 x})

y^{^{'}} + y + 3 sin (x) = 0

y = x^{2} - 14, y = 7 - 4 x

\frac{d}{d x} (\frac{1}{x ^{13}})

\int x^{2} - 2 x d x

What is the derivative of 4/(7x^3) ?
The derivative of 4/(7x^3) is -(12)/(7x^4)
What is the first derivative of 4/(7x^3) ?
The first derivative of 4/(7x^3) is -(12)/(7x^4)