What is the derivative of (x^2+2x-1-(2x^2-3x+6)) ?

The derivative of (x^2+2x-1-(2x^2-3x+6)) is -2x+5

What is the first derivative of (x^2+2x-1-(2x^2-3x+6)) ?

The first derivative of (x^2+2x-1-(2x^2-3x+6)) is -2x+5

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\frac{d}{d x} ((x^{2} + 2 x - 1) - (2 x^{2} - 3 x + 6))

- 2 x + 5

Solution steps

\frac{d}{d x} ((x^{2} + 2 x - 1) - (2 x^{2} - 3 x + 6))

Simplify

(x^{2} + 2 x - 1) - (2 x^{2} - 3 x + 6) : - x^{2} + 5 x - 7

= \frac{d}{d x} (- x^{2} + 5 x - 7)

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= - \frac{d}{d x} (x^{2}) + \frac{d}{d x} (5 x) - \frac{d}{d x} (7)

\frac{d}{d x} (x^{2}) = 2 x

\frac{d}{d x} (5 x) = 5

\frac{d}{d x} (7) = 0

= - 2 x + 5 - 0

Simplify

= - 2 x + 5

\int \frac{1}{( t ^{2} + 1 ) ^{\frac{3}{2}}} d t

\frac{d y}{d x} = (x + y - 2)^{2}

\frac{d ^{2}}{d x ^{2}} (3 x - 7)

2 x^{2} + 5 x + 6, (- 2, 0)

x \to \infty lim (- 1^{x})

What is the derivative of (x^2+2x-1-(2x^2-3x+6)) ?
The derivative of (x^2+2x-1-(2x^2-3x+6)) is -2x+5
What is the first derivative of (x^2+2x-1-(2x^2-3x+6)) ?
The first derivative of (x^2+2x-1-(2x^2-3x+6)) is -2x+5