What is the derivative of sqrt(6x+1) ?

The derivative of sqrt(6x+1) is 3/(sqrt(6x+1))

What is the first derivative of sqrt(6x+1) ?

The first derivative of sqrt(6x+1) is 3/(sqrt(6x+1))

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derivative of

6 x + 1

\frac{3}{6 x + 1}

Solution steps

\frac{d}{d x} (6 x + 1)

Apply the chain rule:

\frac{1}{2 6 x + 1} \frac{d}{d x} (6 x + 1)

= \frac{1}{2 6 x + 1} \frac{d}{d x} (6 x + 1)

\frac{d}{d x} (6 x + 1) = 6

= \frac{1}{2 6 x + 1} \cdot 6

Simplify

\frac{1}{2 6 x + 1} \cdot 6 : \frac{3}{6 x + 1}

= \frac{3}{6 x + 1}

\int \frac{( - 2 cos ( x ) )}{sin ^{2} ( x )} d x

\frac{3 x}{4}

\int \frac{1}{25 x ^{2} - 49} d x

\int \frac{6 - x}{4 x ^{2} - 12 x + 7} d x

t y^{^{'}} + 3 y = t^{2} - t + 7

What is the derivative of sqrt(6x+1) ?
The derivative of sqrt(6x+1) is 3/(sqrt(6x+1))
What is the first derivative of sqrt(6x+1) ?
The first derivative of sqrt(6x+1) is 3/(sqrt(6x+1))