What is the solution for (dy)/(dx)=e^{2x-1}y^2 ?

The solution for (dy)/(dx)=e^{2x-1}y^2 is y=-2/(e^{2x-1)+c_{1}}

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(dy)/(dx)=e^{2x-1}y^2

\frac{d y}{d x} = e^{2 x - 1} y^{2}

y = - \frac{2}{e ^{2 x - 1} + c _{1}}

Solution steps

\frac{d y}{d x} = e^{2 x - 1} y^{2}

Solve separable ODE:

y = - \frac{2}{e ^{2 x - 1} + c _{1}}

y = - \frac{2}{e ^{2 x - 1} + c _{1}}

\int \frac{x ^{2} + 25}{x ^{2}} d x

x = y^{2}, x = 2 - y

f (x) = \frac{- 4 x}{x ^{2} + 1}, (- 1, 2)

cos (θ^{2})

\int x (x^{2} + 4)^{5} d x

What is the solution for (dy)/(dx)=e^{2x-1}y^2 ?
The solution for (dy)/(dx)=e^{2x-1}y^2 is y=-2/(e^{2x-1)+c_{1}}