What is the solution for y^{''}+y=cot(x) ?

The solution for y^{''}+y=cot(x) is y=c_{1}cos(x)+c_{2}sin(x)+sin(x)ln(tan(x/2))

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y^{''}+y=cot(x)

y^{^{''}} + y = cot (x)

y = c_{1} cos (x) + c_{2} sin (x) + sin (x) ln (tan (\frac{x}{2}))

Solution steps

y^{''} (x) + y = cot (x)

Solve linear ODE:

y = c_{1} cos (x) + c_{2} sin (x) + sin (x) ln (tan (\frac{x}{2}))

y = c_{1} cos (x) + c_{2} sin (x) + sin (x) ln (tan (\frac{x}{2}))

\frac{\partial}{\partial y} (ln (3 + x^{2} y^{2}))

\frac{d}{d x} (\frac{sin ( x )}{1 + 2 cos ( x )})

y = e^{x} cos (x)

\int x^{2} x + 1 d x

\frac{d}{d x} (sin (x) + x)

What is the solution for y^{''}+y=cot(x) ?
The solution for y^{''}+y=cot(x) is y=c_{1}cos(x)+c_{2}sin(x)+sin(x)ln(tan(x/2))