What is the derivative of sin(x+x) ?

The derivative of sin(x+x) is cos(x)+1

What is the first derivative of sin(x+x) ?

The first derivative of sin(x+x) is cos(x)+1

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\frac{d}{d x} (sin (x) + x)

cos (x) + 1

Solution steps

\frac{d}{d x} (sin (x) + x)

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (sin (x)) + \frac{d x}{d x}

\frac{d}{d x} (sin (x)) = cos (x)

\frac{d x}{d x} = 1

= cos (x) + 1

\int \frac{2 x}{1 - 4 x ^{4}} d x

\int \frac{z ^{2}}{z ^{3} + 1} d z

- 9 (5 x^{2} + 4)^{- 6}

x + y = x^{3} + y^{2}

\int e^{t a n (x)} sec^{2} (x) d x

What is the derivative of sin(x+x) ?
The derivative of sin(x+x) is cos(x)+1
What is the first derivative of sin(x+x) ?
The first derivative of sin(x+x) is cos(x)+1