What is the integral of e^{tan(x)}sec^2(x) ?

The integral of e^{tan(x)}sec^2(x) is e^{tan(x)}+C

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integral of e^{tan(x)}sec^2(x)

\int e^{t a n (x)} sec^{2} (x) d x

e^{t a n (x)} + C

Solution steps

\int e^{t a n (x)} sec^{2} (x) d x

Apply u-substitution

: \int e^{u} d u

= \int e^{u} d u

Use the common integral:

\int e^{u} d u = e^{u}

= e^{u}

Substitute back

u = tan (x)

= e^{t a n (x)}

Add a constant to the solution

= e^{t a n (x)} + C

y = 4 x^{2}

f (x) = ln (7)

\int_{0}^{2} x^{3} e^{- x^{2}} d x

x \to 0 lim (\frac{1 + x}{x ^{2}})

4 (x - (\frac{1}{x})^{4})

What is the integral of e^{tan(x)}sec^2(x) ?
The integral of e^{tan(x)}sec^2(x) is e^{tan(x)}+C