What is the derivative of 2x^3-3x^2+2x ?

The derivative of 2x^3-3x^2+2x is 6x^2-6x+2

What is the first derivative of 2x^3-3x^2+2x ?

The first derivative of 2x^3-3x^2+2x is 6x^2-6x+2

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\frac{d}{d x} (2 x^{3} - 3 x^{2} + 2 x)

6 x^{2} - 6 x + 2

Solution steps

\frac{d}{d x} (2 x^{3} - 3 x^{2} + 2 x)

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (2 x^{3}) - \frac{d}{d x} (3 x^{2}) + \frac{d}{d x} (2 x)

\frac{d}{d x} (2 x^{3}) = 6 x^{2}

\frac{d}{d x} (3 x^{2}) = 6 x

\frac{d}{d x} (2 x) = 2

= 6 x^{2} - 6 x + 2

6 x^{4} - 9 x y - 7 y^{2} = 104, (- 2, 2)

n = 1 \sum \infty \frac{- n}{n ^{2} + 1}

x \to 2 lim (3 x^{2} - 5 x + 2)

e^{y} d x - e^{- x} d y = 0, y (0) = 0

\frac{d ^{2}}{d r ^{2}} (π r^{2})

What is the derivative of 2x^3-3x^2+2x ?
The derivative of 2x^3-3x^2+2x is 6x^2-6x+2
What is the first derivative of 2x^3-3x^2+2x ?
The first derivative of 2x^3-3x^2+2x is 6x^2-6x+2