What is maclaurin 9cos(-x) ?

The answer to maclaurin 9cos(-x) is 9-9/2 x^2+3/8 x^4-1/80 x^6+1/4480 x^8+\ldots

Popular >

maclaurin 9cos(-x)

maclaurin

9 cos (- x)

9 - \frac{9}{2} x^{2} + \frac{3}{8} x^{4} - \frac{1}{80} x^{6} + \frac{1}{4480} x^{8} + \dots

Solution steps

Apply the Maclaurin Formula

= 9 + \frac{\frac{d}{d x} ( 9 cos ( - x ) ) ( 0 )}{1 !} x + \frac{\frac{d ^{2}}{d x ^{2}} ( 9 cos ( - x ) ) ( 0 )}{2 !} x^{2} + \frac{\frac{d ^{3}}{d x ^{3}} ( 9 cos ( - x ) ) ( 0 )}{3 !} x^{3} + \dots

Evaluate Derivatives

= 9 + \frac{0}{1 !} x + \frac{- 9}{2 !} x^{2} + \frac{0}{3 !} x^{3} + \frac{9}{4 !} x^{4} + \frac{0}{5 !} x^{5} + \frac{- 9}{6 !} x^{6} + \frac{0}{7 !} x^{7} + \frac{9}{8 !} x^{8} + \dots

Refine

= 9 - \frac{9}{2} x^{2} + \frac{3}{8} x^{4} - \frac{1}{80} x^{6} + \frac{1}{4480} x^{8} + \dots

\int \frac{1}{x ^{2} + 8 x} d x

\frac{d y}{d x} = \frac{y}{( x + 1 )} + 4 x^{2} + 4 x

\frac{\partial}{\partial v} (cos (u))

\frac{\partial}{\partial y} (2 x y - 3 x^{2})

x \to 1 lim (\frac{2 x + 1}{x + 2})

What is maclaurin 9cos(-x) ?
The answer to maclaurin 9cos(-x) is 9-9/2 x^2+3/8 x^4-1/80 x^6+1/4480 x^8+\ldots