What is area sin(x),[ 11/9 pi, 12/8 pi] ?

The answer to area sin(x),[ 11/9 pi, 12/8 pi] is -cos((11pi)/9)

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area sin(x),[ 11/9 pi, 12/8 pi]

area

sin (x), [\frac{11}{9} π, \frac{12}{8} π]

- cos (\frac{11 π}{9})

Decimal

0.76604 \dots

Solution steps

Apply the area formula:

\int_{\frac{11}{9} π}^{\frac{12}{8} π} ∣ sin (x) ∣ d x

Solve

\int_{\frac{11}{9} π}^{\frac{12}{8} π} ∣ sin (x) ∣ d x : - cos (\frac{11 π}{9})

The area is:

= - cos (\frac{11 π}{9})

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What is area sin(x),[ 11/9 pi, 12/8 pi] ?
The answer to area sin(x),[ 11/9 pi, 12/8 pi] is -cos((11pi)/9)