What is the limit as x approaches-1-of g(x) ?

The limit as x approaches-1-of g(x) is g(-1)

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limit as x approaches-1-of g(x)

x \to - 1 - lim (g (x))

g (- 1)

Solution steps

x \to - 1 - lim (g (x))

Plug in the value

x = - 1

, assuming the function is continuous at this point

= g (- 1)

f (x) = \frac{3}{( 2 x + 1 ) ^{\frac{5}{2}}}

x y^{^{'}} - y = - x^{2} + 2 x + 2

\int \frac{x ^{2} + 1}{x ^{2} - x} d x

\frac{\partial}{\partial y} (8 x ln (x y))

t^{2} \cdot y^{^{'}} + t \cdot y = 5

What is the limit as x approaches-1-of g(x) ?
The limit as x approaches-1-of g(x) is g(-1)