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Popular >

t^2y^'+ty=5

Solution

t^{2} \cdot y^{^{'}} + t \cdot y = 5

Solution

y = \frac{5 ln ( t )}{t} + \frac{c _{1}}{t}

Solution steps

t^{2} \cdot y^{'} (t) + t \cdot y = 5

Solve linear ODE:

y = \frac{5 ln ( t )}{t} + \frac{c _{1}}{t}

y = \frac{5 ln ( t )}{t} + \frac{c _{1}}{t}

Graph

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Frequently Asked Questions (FAQ)

What is the solution for t^2*y^'+t*y=5 ?
The solution for t^2*y^'+t*y=5 is y=(5ln(t))/t+(c_{1})/t