What is inverse oflaplace {1/(s^4)} ?

The answer to inverse oflaplace {1/(s^4)} is (t^3)/6

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

inverse oflaplace {1/(s^4)}

inverse laplace

{\frac{1}{s ^{4}}}

\frac{t ^{3}}{6}

Solution steps

L^{- 1} {\frac{1}{s ^{4}}}

= L^{- 1} {\frac{1}{6} \cdot \frac{6}{s ^{4}}}

Use the constant multiplication property of Inverse Laplace Transform:

For function

f (t)

and constant

a : L^{- 1} {a \cdot f (t)} = a \cdot L^{- 1} {f (t)}

= \frac{1}{6} L^{- 1} {\frac{6}{s ^{4}}}

Use Inverse Laplace Transform table:

L^{- 1} {\frac{( n ) !}{s ^{n + 1}}} = t^{n}

L^{- 1} {\frac{6}{s ^{4}}} = t^{3}

= \frac{1}{6} t^{3}

= \frac{t ^{3}}{6}

2, - 5, y = 2 x^{2} + 12, y = 0

x \to \infty lim (4 + \frac{1}{x})

\frac{\partial}{\partial x} (\frac{1}{3 x - 2})

\int sin (24 x) cos (17 x) d x

\int x - \frac{x ^{2}}{2} + c d x

What is inverse oflaplace {1/(s^4)} ?
The answer to inverse oflaplace {1/(s^4)} is (t^3)/6