What is the derivative of 2xsqrt(y-1) ?

The derivative of 2xsqrt(y-1) is 2sqrt(y-1)+(x\frac{dy)/(dx)}{sqrt(y-1)}

What is the first derivative of 2xsqrt(y-1) ?

The first derivative of 2xsqrt(y-1) is 2sqrt(y-1)+(x\frac{dy)/(dx)}{sqrt(y-1)}

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

\frac{d}{d x} (2 x y - 1)

2 y - 1 + \frac{x \frac{d y}{d x}}{y - 1}

Solution steps

\frac{d}{d x} (2 x y - 1)

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= 2 \frac{d}{d x} (x y - 1)

Apply the Product Rule:

(f \cdot g)^{'} = f^{'} \cdot g + f \cdot g^{'}

f = x, g = y - 1

= 2 (\frac{d x}{d x} y - 1 + \frac{d}{d x} (y - 1) x)

\frac{d x}{d x} = 1

\frac{d}{d x} (y - 1) = \frac{\frac{d y}{d x}}{2 y - 1}

= 2 (1 \cdot y - 1 + \frac{\frac{d y}{d x}}{2 y - 1} x)

Simplify

2 (1 \cdot y - 1 + \frac{\frac{d y}{d x}}{2 y - 1} x) : 2 y - 1 + \frac{x \frac{d y}{d x}}{y - 1}

= 2 y - 1 + \frac{x \frac{d y}{d x}}{y - 1}

x \to 3 lim (2 x - 8)

\frac{d}{d x} (\frac{600 x}{2 x ^{2} + 25})

\int \frac{8 x ^{2}}{4 x + 6} d x

\int 9 t^{4} + 4 t^{2} d t

\frac{\partial}{\partial x} (x + y - 320)

What is the derivative of 2xsqrt(y-1) ?
The derivative of 2xsqrt(y-1) is 2sqrt(y-1)+(x\frac{dy)/(dx)}{sqrt(y-1)}
What is the first derivative of 2xsqrt(y-1) ?
The first derivative of 2xsqrt(y-1) is 2sqrt(y-1)+(x\frac{dy)/(dx)}{sqrt(y-1)}