What is (\partial)/(\partial y)(sin(2x-y)) ?

The answer to (\partial)/(\partial y)(sin(2x-y)) is -cos(2x-y)

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(\partial)/(\partial y)(sin(2x-y))

\frac{\partial}{\partial y} (sin (2 x - y))

- cos (2 x - y)

Solution steps

\frac{\partial}{\partial y} (sin (2 x - y))

Treat

x

as a constant

Apply the chain rule:

cos (2 x - y) \frac{\partial}{\partial y} (2 x - y)

= cos (2 x - y) \frac{\partial}{\partial y} (2 x - y)

\frac{\partial}{\partial y} (2 x - y) = - 1

= cos (2 x - y) (- 1)

Simplify

= - cos (2 x - y)

\int (1 + e^{- a t})^{\frac{3}{2}} e^{- a t} d t

3 e^{x} + \frac{4}{3 x}

y = (\frac{1}{2 x + 1})^{2}

x \to a lim ((1 + \frac{1}{x})^{x})

\frac{d}{d x} (\frac{1}{10 - x})

What is (\partial)/(\partial y)(sin(2x-y)) ?
The answer to (\partial)/(\partial y)(sin(2x-y)) is -cos(2x-y)