What is the derivative of y=(1/(2x+1))^2 ?

The derivative of y=(1/(2x+1))^2 is -4/((2x+1)^3)

What is the first derivative of y=(1/(2x+1))^2 ?

The first derivative of y=(1/(2x+1))^2 is -4/((2x+1)^3)

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derivative of

y = (\frac{1}{2 x + 1})^{2}

- \frac{4}{( 2 x + 1 ) ^{3}}

Solution steps

\frac{d}{d x} ((\frac{1}{2 x + 1})^{2})

Apply the chain rule:

2 \cdot \frac{1}{2 x + 1} \frac{d}{d x} (\frac{1}{2 x + 1})

= 2 \cdot \frac{1}{2 x + 1} \frac{d}{d x} (\frac{1}{2 x + 1})

\frac{d}{d x} (\frac{1}{2 x + 1}) = - \frac{2}{( 2 x + 1 ) ^{2}}

= 2 \cdot \frac{1}{2 x + 1} (- \frac{2}{( 2 x + 1 ) ^{2}})

Simplify

2 \cdot \frac{1}{2 x + 1} (- \frac{2}{( 2 x + 1 ) ^{2}}) : - \frac{4}{( 2 x + 1 ) ^{3}}

= - \frac{4}{( 2 x + 1 ) ^{3}}

x \to a lim ((1 + \frac{1}{x})^{x})

\frac{d}{d x} (\frac{1}{10 - x})

\int (y e^{x y}) d x

\int \frac{( 3 x - 2 )}{4 x ^{2} - 4 x + 5} d x

\int 1. 8^{0.045 x} d x

What is the derivative of y=(1/(2x+1))^2 ?
The derivative of y=(1/(2x+1))^2 is -4/((2x+1)^3)
What is the first derivative of y=(1/(2x+1))^2 ?
The first derivative of y=(1/(2x+1))^2 is -4/((2x+1)^3)