What is the integral from 1 to 0 of (4-5x^2) ?

The integral from 1 to 0 of (4-5x^2) is -7/3

Popular >

integral from 1 to 0 of (4-5x^2)

\int_{1}^{0} (4 - 5 x^{2}) d x

- \frac{7}{3}

Decimal

- 2.33333 \dots

Solution steps

\int_{1}^{0} 4 - 5 x^{2} d x

\int_{a}^{b} f (x) d x = - \int_{b}^{a} f (x) d x, a < b

= - \int_{0}^{1} 4 - 5 x^{2} d x

Apply the Sum Rule:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= - (\int_{0}^{1} 4 d x - \int_{0}^{1} 5 x^{2} d x)

\int_{0}^{1} 4 d x = 4

\int_{0}^{1} 5 x^{2} d x = \frac{5}{3}

= - (4 - \frac{5}{3})

Join

4 - \frac{5}{3} : \frac{7}{3}

= - \frac{7}{3}

\int_{0}^{1.5} 100 x d x

\frac{d}{d x} (\frac{x ^{2}}{e ^{x}})

\int 13 tan^{3} (x) sec (x) d x

\frac{\partial}{\partial x} (2 y - x e^{(x y)})

\frac{d y}{d t} + \frac{3 t}{t ^{2} + 1} y = \frac{6 t}{t ^{2} + 1}

What is the integral from 1 to 0 of (4-5x^2) ?
The integral from 1 to 0 of (4-5x^2) is -7/3