What is (\partial)/(\partial y)(tan(2+2x^2y^3z^2)) ?

The answer to (\partial)/(\partial y)(tan(2+2x^2y^3z^2)) is sec^2(2+2x^2y^3z^2)*6x^2z^2y^2

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(\partial)/(\partial y)(tan(2+2x^2y^3z^2))

\frac{\partial}{\partial y} (tan (2 + 2 x^{2} y^{3} z^{2}))

sec^{2} (2 + 2 x^{2} y^{3} z^{2}) \cdot 6 x^{2} z^{2} y^{2}

Solution steps

\frac{\partial}{\partial y} (tan (2 + 2 x^{2} y^{3} z^{2}))

Treat

x, z

as constants

Apply the chain rule:

sec^{2} (2 + 2 x^{2} y^{3} z^{2}) \frac{\partial}{\partial y} (2 + 2 x^{2} y^{3} z^{2})

= sec^{2} (2 + 2 x^{2} y^{3} z^{2}) \frac{\partial}{\partial y} (2 + 2 x^{2} y^{3} z^{2})

\frac{\partial}{\partial y} (2 + 2 x^{2} y^{3} z^{2}) = 6 x^{2} z^{2} y^{2}

= sec^{2} (2 + 2 x^{2} y^{3} z^{2}) \cdot 6 x^{2} z^{2} y^{2}

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What is (\partial)/(\partial y)(tan(2+2x^2y^3z^2)) ?
The answer to (\partial)/(\partial y)(tan(2+2x^2y^3z^2)) is sec^2(2+2x^2y^3z^2)*6x^2z^2y^2