What is the derivative of f(x)=2e^x(cos(x)-sin(x)) ?

The derivative of f(x)=2e^x(cos(x)-sin(x)) is -4e^xsin(x)

What is the first derivative of f(x)=2e^x(cos(x)-sin(x)) ?

The first derivative of f(x)=2e^x(cos(x)-sin(x)) is -4e^xsin(x)

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derivative of

f (x) = 2 e^{x} (cos (x) - sin (x))

- 4 e^{x} sin (x)

Solution steps

\frac{d}{d x} (2 e^{x} (cos (x) - sin (x)))

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= 2 \frac{d}{d x} (e^{x} (cos (x) - sin (x)))

Apply the Product Rule:

(f \cdot g)^{'} = f^{'} \cdot g + f \cdot g^{'}

f = e^{x}, g = cos (x) - sin (x)

= 2 (\frac{d}{d x} (e^{x}) (cos (x) - sin (x)) + \frac{d}{d x} (cos (x) - sin (x)) e^{x})

\frac{d}{d x} (e^{x}) = e^{x}

\frac{d}{d x} (cos (x) - sin (x)) = - sin (x) - cos (x)

= 2 (e^{x} (cos (x) - sin (x)) + (- sin (x) - cos (x)) e^{x})

Simplify

2 (e^{x} (cos (x) - sin (x)) + (- sin (x) - cos (x)) e^{x}) : - 4 e^{x} sin (x)

= - 4 e^{x} sin (x)

30 y^{^{''}} + 19 y^{^{'}} - 5 y = 0

(3, 4), (5, - 4)

\frac{d y}{d x} = \frac{- x e ^{- x^{2}}}{y}

y = \frac{x - 4}{x - 5}, (6, 2)

\frac{d}{d x} (e^{x - 5})

What is the derivative of f(x)=2e^x(cos(x)-sin(x)) ?
The derivative of f(x)=2e^x(cos(x)-sin(x)) is -4e^xsin(x)
What is the first derivative of f(x)=2e^x(cos(x)-sin(x)) ?
The first derivative of f(x)=2e^x(cos(x)-sin(x)) is -4e^xsin(x)