What is the (sqrt(4-x^2))^' ?

The (sqrt(4-x^2))^' is -x/(sqrt(4-x^2))

What is the first (sqrt(4-x^2))^' ?

The first (sqrt(4-x^2))^' is -x/(sqrt(4-x^2))

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(4 - x^{2})^{^{'}}

- \frac{x}{4 - x ^{2}}

Solution steps

(4 - x^{2})^{'}

Apply the chain rule:

\frac{1}{2 4 - x ^{2}} (4 - x^{2})^{'}

= \frac{1}{2 4 - x ^{2}} (4 - x^{2})^{'}

(4 - x^{2})^{'} = - 2 x

= \frac{1}{2 4 - x ^{2}} (- 2 x)

Simplify

\frac{1}{2 4 - x ^{2}} (- 2 x) : - \frac{x}{4 - x ^{2}}

= - \frac{x}{4 - x ^{2}}

\frac{d}{d x} (sin (x) e^{- c o s (x)})

x \to 100000 lim (x^{3} + 2 x + 1)

\frac{d}{d x} (2 x^{2} - 2 x + c)

\frac{d ^{2}}{d x ^{2}} (x (2 x + 1)^{5})

\int - 4 x e^{x} d x

What is the (sqrt(4-x^2))^' ?
The (sqrt(4-x^2))^' is -x/(sqrt(4-x^2))
What is the first (sqrt(4-x^2))^' ?
The first (sqrt(4-x^2))^' is -x/(sqrt(4-x^2))