What is the tangent of y=-2-7x^2,(-2,-30) ?

The tangent of y=-2-7x^2,(-2,-30) is y=28x+26

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tangent of y=-2-7x^2,(-2,-30)

tangent of

y = - 2 - 7 x^{2}, (- 2, - 30)

y = 28 x + 26

Solution steps

Find the slope of

y = - 2 - 7 x^{2} : \frac{d y}{d x} = - 14 x

EN : T i tl e G e n er a l Eq u a t i o n Sl o p e A t P o in t 2 Eq : m = 28

Find the line with slope m=

28

and passing through

(- 2, - 30) : y = 28 x + 26

y = 28 x + 26

\int \frac{3 cos ( x )}{sin ^{2} ( x ) + sin ( x )} d x

x^{2} - 35, 5 - 3 x

n = 1 \sum \infty \frac{1}{n} - \frac{1}{n ^{2}}

\int_{4}^{7} \frac{x}{x ^{2} - 2} d x

n = 3 \sum \infty \frac{n}{e ^{3 n}}

What is the tangent of y=-2-7x^2,(-2,-30) ?
The tangent of y=-2-7x^2,(-2,-30) is y=28x+26