What is area x^2+3x-2,-x^2-3x+6 ?

The answer to area x^2+3x-2,-x^2-3x+6 is 125/3

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

area x^2+3x-2,-x^2-3x+6

area

x^{2} + 3 x - 2, - x^{2} - 3 x + 6

\frac{125}{3}

Decimal

41.66666 \dots

Solution steps

Apply the area formula:

\int_{- 4}^{1} x^{2} + 3 x - 2 - (- x^{2} - 3 x + 6) d x

Solve

\int_{- 4}^{1} x^{2} + 3 x - 2 - (- x^{2} - 3 x + 6) d x : \frac{125}{3}

The area is:

= \frac{125}{3}

n = 0 \sum \infty (\frac{3}{5})^{\frac{n}{2}}

\frac{d}{d x} ((\frac{3 x - 4}{5 x + 2})^{- 5})

ln (\frac{x}{4 x ^{2} + x})

\frac{d}{d x} (\frac{1}{2} \cdot 3 x)

\int_{0}^{1} e^{- 3 x} d x

What is area x^2+3x-2,-x^2-3x+6 ?
The answer to area x^2+3x-2,-x^2-3x+6 is 125/3