What is the solution for (dy)/(dx)-6/x y=(y^4)/(x^{15)},y(1)=1 ?

The solution for (dy)/(dx)-6/x y=(y^4)/(x^{15)},y(1)=1 is y=(\sqrt[3]{4}x^6)/(\sqrt[3]{-3x^4+7)}

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

(dy)/(dx)-6/x y=(y^4)/(x^{15)},y(1)=1

\frac{d y}{d x} - \frac{6}{x} y = \frac{y ^{4}}{x ^{15}}, y (1) = 1

y = \frac{3 4 x ^{6}}{3 - 3 x ^{4} + 7}

Solution steps

\frac{d y}{d x} - \frac{6}{x} y = \frac{y ^{4}}{x ^{15}}

Solve Bernoulli ODE:

y = \frac{3 4 x ^{6}}{3 - 3 x ^{4} + 7}

y = \frac{3 4 x ^{6}}{3 - 3 x ^{4} + 7}

x \frac{d y}{d x} = - 4 y + x^{3} - x

\frac{d x}{d t} = 4 x (9 - x)

(3 x - 2)^{3} (x^{3} + 1)^{2}

\int x^{3} x^{2} + 12 d x

\frac{\partial}{\partial x} (x y^{2} z^{3})

What is the solution for (dy)/(dx)-6/x y=(y^4)/(x^{15)},y(1)=1 ?
The solution for (dy)/(dx)-6/x y=(y^4)/(x^{15)},y(1)=1 is y=(\sqrt[3]{4}x^6)/(\sqrt[3]{-3x^4+7)}