What is (\partial)/(\partial y)(ln(x-4y)) ?

The answer to (\partial)/(\partial y)(ln(x-4y)) is -4/(x-4y)

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

(\partial)/(\partial y)(ln(x-4y))

\frac{\partial}{\partial y} (ln (x - 4 y))

- \frac{4}{x - 4 y}

Solution steps

\frac{\partial}{\partial y} (ln (x - 4 y))

Treat

x

as a constant

Apply the chain rule:

\frac{1}{x - 4 y} \frac{\partial}{\partial y} (x - 4 y)

= \frac{1}{x - 4 y} \frac{\partial}{\partial y} (x - 4 y)

\frac{\partial}{\partial y} (x - 4 y) = - 4

= \frac{1}{x - 4 y} (- 4)

Simplify

\frac{1}{x - 4 y} (- 4) : - \frac{4}{x - 4 y}

= - \frac{4}{x - 4 y}

x \to 1 lim (2 x^{3} + x - 1)

f (x) =, \frac{1}{x}

f (x) = - 3 tan (x) - e^{- x}

y^{^{''}} - 3 y^{^{'}} = (3 t + 8) sin (3 t)

\frac{d}{d x} (\frac{e ^{4 x}}{x ^{2}})

What is (\partial)/(\partial y)(ln(x-4y)) ?
The answer to (\partial)/(\partial y)(ln(x-4y)) is -4/(x-4y)