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Popular >

xy^'+y=-2xy^2

Solution

x y^{^{'}} + y = - 2 x y^{2}

Solution

y = \frac{1}{x ( 2 ln ( x ) + c _{1} )}

Solution steps

x y^{'} (x) + y = - 2 x y^{2}

Solve Bernoulli ODE:

y = \frac{1}{x ( 2 ln ( x ) + c _{1} )}

y = \frac{1}{x ( 2 ln ( x ) + c _{1} )}

Graph

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limit as x approaches 0 of (x+2)^3

x \to 0 lim ((x + 2)^{3})

Frequently Asked Questions (FAQ)

What is the solution for xy^'+y=-2xy^2 ?
The solution for xy^'+y=-2xy^2 is y= 1/(x(2ln(x)+c_{1))}