What is the solution for (y/x+9x)dx+(ln(x)-4)dy=0 ?

The solution for (y/x+9x)dx+(ln(x)-4)dy=0 is y=-(9x^2)/(2(ln(x)-4))+(c_{1})/(ln(x)-4)

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(y/x+9x)dx+(ln(x)-4)dy=0

(\frac{y}{x} + 9 x) d x + (ln (x) - 4) d y = 0

y = - \frac{9 x ^{2}}{2 ( ln ( x ) - 4 )} + \frac{c _{1}}{ln ( x ) - 4}

Solution steps

(\frac{y}{x} + 9 x) d x + (ln (x) - 4) d y = 0

Solve linear ODE:

y = - \frac{9 x ^{2}}{2 ( ln ( x ) - 4 )} + \frac{c _{1}}{ln ( x ) - 4}

y = - \frac{9 x ^{2}}{2 ( ln ( x ) - 4 )} + \frac{c _{1}}{ln ( x ) - 4}

\frac{\partial}{\partial x} (x^{2} + 3 x y + y^{2})

y^{^{''}} - 16 y^{^{'}} + 64 y = 0

\frac{d}{d x} (ln (\frac{( x + 2 ) e ^{3 x}}{x ^{2} + 1}))

\frac{d y}{d x} = (\frac{9 x}{9 x ^{2} - 1}) e^{- y}

\int - \frac{2 x}{( 1 + x ^{2} ) ^{2}} d x

What is the solution for (y/x+9x)dx+(ln(x)-4)dy=0 ?
The solution for (y/x+9x)dx+(ln(x)-4)dy=0 is y=-(9x^2)/(2(ln(x)-4))+(c_{1})/(ln(x)-4)