What is area x^2-4,x=0,-4,3 ?

The answer to area x^2-4,x=0,-4,3 is (-14sqrt(7)+64)/3+14sqrt(7)-28

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area x^2-4,x=0,-4,3

area

x^{2} - 4, x = 0, - 4, 3

\frac{- 14 7 + 64}{3} + 147 - 28

Decimal

18.02701 \dots

Solution steps

Apply the area formula:

\int_{- 4}^{0} x^{2} - 7 d x

Solve

\int_{- 4}^{0} x^{2} - 7 d x : \frac{- 14 7 + 64}{3} + 147 - 28

The area is:

= \frac{- 14 7 + 64}{3} + 147 - 28

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\frac{d}{d x} (b x e^{2 x y})

\int 1 + \frac{9 x}{4} d x

What is area x^2-4,x=0,-4,3 ?
The answer to area x^2-4,x=0,-4,3 is (-14sqrt(7)+64)/3+14sqrt(7)-28