What is the derivative of f(x)=8xe^x ?

The derivative of f(x)=8xe^x is 8(e^x+e^xx)

What is the first derivative of f(x)=8xe^x ?

The first derivative of f(x)=8xe^x is 8(e^x+e^xx)

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derivative of

f (x) = 8 x e^{x}

8 (e^{x} + e^{x} x)

Solution steps

\frac{d}{d x} (8 x e^{x})

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= 8 \frac{d}{d x} (x e^{x})

Apply the Product Rule:

(f \cdot g)^{'} = f^{'} \cdot g + f \cdot g^{'}

f = x, g = e^{x}

= 8 (\frac{d x}{d x} e^{x} + \frac{d}{d x} (e^{x}) x)

\frac{d x}{d x} = 1

\frac{d}{d x} (e^{x}) = e^{x}

= 8 (1 \cdot e^{x} + e^{x} x)

Simplify

= 8 (e^{x} + e^{x} x)

\frac{d y}{d t} = 0.75 y - 0.00003 y^{2}

\int \frac{3}{x ^{5}} - \frac{2}{x ^{2}} - \frac{6}{x} d x

\int \frac{1}{2 + tan ( x )} d x

\int \frac{x + 4}{x ^{2} + 8 x - 20} d x

y^{^{'}} = 2 x y - x

What is the derivative of f(x)=8xe^x ?
The derivative of f(x)=8xe^x is 8(e^x+e^xx)
What is the first derivative of f(x)=8xe^x ?
The first derivative of f(x)=8xe^x is 8(e^x+e^xx)