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Popular >

y^'=2xy-x

Solution

y^{^{'}} = 2 x y - x

Solution

y = \frac{e ^{x^{2} + c_{1}}}{2} + \frac{1}{2}

Solution steps

y^{'} (x) = 2 x y - x

Solve separable ODE:

y = \frac{e ^{x^{2} + c_{1}}}{2} + \frac{1}{2}

y = \frac{e ^{x^{2} + c_{1}}}{2} + \frac{1}{2}

Graph

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\int (8 x - 3) ln (x) d x

Frequently Asked Questions (FAQ)

What is the solution for y^'=2xy-x ?
The solution for y^'=2xy-x is y=(e^{x^2+c_{1}})/2+1/2