What is (d^4)/(dx^4)(sqrt(x)) ?

The answer to (d^4)/(dx^4)(sqrt(x)) is -(15)/(16x^{7/2)}

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(d^4)/(dx^4)(sqrt(x))

\frac{d ^{4}}{d x ^{4}} (x)

- \frac{15}{16 x ^{\frac{7}{2}}}

Solution steps

\frac{d ^{4}}{d x ^{4}} (x)

\frac{d}{d x} (x) = \frac{1}{2 x}

= \frac{d ^{3}}{d x ^{3}} (\frac{1}{2 x})

\frac{d}{d x} (\frac{1}{2 x}) = - \frac{1}{4 x ^{\frac{3}{2}}}

= \frac{d ^{2}}{d x ^{2}} (- \frac{1}{4 x ^{\frac{3}{2}}})

\frac{d}{d x} (- \frac{1}{4 x ^{\frac{3}{2}}}) = \frac{3}{8 x ^{\frac{5}{2}}}

= \frac{d}{d x} (\frac{3}{8 x ^{\frac{5}{2}}})

\frac{d}{d x} (\frac{3}{8 x ^{\frac{5}{2}}}) = - \frac{15}{16 x ^{\frac{7}{2}}}

= - \frac{15}{16 x ^{\frac{7}{2}}}

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What is (d^4)/(dx^4)(sqrt(x)) ?
The answer to (d^4)/(dx^4)(sqrt(x)) is -(15)/(16x^{7/2)}