What is the integral of e^{5x^2} ?

The integral of e^{5x^2} is (sqrt(pi))/(2sqrt(5))\erfi(sqrt(5)x)+C

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integral of e^{5x^2}

\int e^{5 x^{2}} d x

\frac{π}{2 5} erfi (5 x) + C

Solution steps

\int e^{5 x^{2}} d x

= \int e^{(5 x)^{2}} d x

Apply u-substitution

: \int e^{u^{2}} \frac{1}{5} d u

= \int e^{u^{2}} \frac{1}{5} d u

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= \frac{1}{5} \cdot \int e^{u^{2}} d u

Use the nonelementary integral:

\int e^{u^{2}} d u = \frac{π}{2} erfi (u)

= \frac{1}{5} \cdot \frac{π}{2} erfi (u)

Substitute back

u = 5 x

= \frac{1}{5} \cdot \frac{π}{2} erfi (5 x)

Simplify

\frac{1}{5} \cdot \frac{π}{2} erfi (5 x) : \frac{π}{2 5} erfi (5 x)

= \frac{π}{2 5} erfi (5 x)

Add a constant to the solution

= \frac{π}{2 5} erfi (5 x) + C

f (x) = ln (1 - x^{2} + 2 x^{4}), at x = 1

\int \frac{1}{( 3 x - 2 ) ^{2}} d x

n = 1 \sum \infty \frac{4}{n ( n + 3 )}

\frac{\partial}{\partial y} (ln (x - 2 y))

\int x ln (2) + \frac{3}{2} x d x

What is the integral of e^{5x^2} ?
The integral of e^{5x^2} is (sqrt(pi))/(2sqrt(5))\erfi(sqrt(5)x)+C