What is (\partial)/(\partial y)(ln(x-2y)) ?

The answer to (\partial)/(\partial y)(ln(x-2y)) is -2/(x-2y)

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(\partial)/(\partial y)(ln(x-2y))

\frac{\partial}{\partial y} (ln (x - 2 y))

- \frac{2}{x - 2 y}

Solution steps

\frac{\partial}{\partial y} (ln (x - 2 y))

Treat

x

as a constant

Apply the chain rule:

\frac{1}{x - 2 y} \frac{\partial}{\partial y} (x - 2 y)

= \frac{1}{x - 2 y} \frac{\partial}{\partial y} (x - 2 y)

\frac{\partial}{\partial y} (x - 2 y) = - 2

= \frac{1}{x - 2 y} (- 2)

Simplify

\frac{1}{x - 2 y} (- 2) : - \frac{2}{x - 2 y}

= - \frac{2}{x - 2 y}

\int x ln (2) + \frac{3}{2} x d x

x y^{^{'}} + 2 y = 4 sin (x)

\frac{d}{d x} (x^{2} + 8 x)

\frac{\partial}{\partial x} (x e^{- 2 x})

(3 x - 2 x^{2})^{3}

What is (\partial)/(\partial y)(ln(x-2y)) ?
The answer to (\partial)/(\partial y)(ln(x-2y)) is -2/(x-2y)