What is the solution for y^{''''}=y ?

The solution for y^{''''}=y is y=c_{1}e^t+c_{2}e^{-t}+c_{3}cos(t)+c_{4}sin(t)

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y^{''''}=y

y^{^{''''}} = y

y = c_{1} e^{t} + c_{2} e^{- t} + c_{3} cos (t) + c_{4} sin (t)

Solution steps

y^{(4)} (t) = y

Solve linear ODE:

y = c_{1} e^{t} + c_{2} e^{- t} + c_{3} cos (t) + c_{4} sin (t)

y = c_{1} e^{t} + c_{2} e^{- t} + c_{3} cos (t) + c_{4} sin (t)

\frac{d}{d x} (- 64 cos (4 x))

\int 3 x^{\frac{3}{2}} d x

\int \frac{sin ( 2 x )}{36 + cos ^{2} ( x )} d x

0.5 q^{^{''}} + 10 q^{^{'}} + 100 q = 150

\int_{0}^{\infty} 3 e^{- x} d x

What is the solution for y^{''''}=y ?
The solution for y^{''''}=y is y=c_{1}e^t+c_{2}e^{-t}+c_{3}cos(t)+c_{4}sin(t)