What is the derivative of 5sec(5xtan(5x)) ?

The derivative of 5sec(5xtan(5x)) is 5(5tan^2(5x)sec(5x)+5sec^3(5x))

What is the first derivative of 5sec(5xtan(5x)) ?

The first derivative of 5sec(5xtan(5x)) is 5(5tan^2(5x)sec(5x)+5sec^3(5x))

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\frac{d}{d x} (5 sec (5 x) tan (5 x))

5 (5 tan^{2} (5 x) sec (5 x) + 5 sec^{3} (5 x))

Solution steps

\frac{d}{d x} (5 sec (5 x) tan (5 x))

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= 5 \frac{d}{d x} (sec (5 x) tan (5 x))

Apply the Product Rule:

(f \cdot g)^{'} = f^{'} \cdot g + f \cdot g^{'}

f = sec (5 x), g = tan (5 x)

= 5 (\frac{d}{d x} (sec (5 x)) tan (5 x) + \frac{d}{d x} (tan (5 x)) sec (5 x))

\frac{d}{d x} (sec (5 x)) = sec (5 x) tan (5 x) \cdot 5

\frac{d}{d x} (tan (5 x)) = sec^{2} (5 x) \cdot 5

= 5 (sec (5 x) tan (5 x) \cdot 5 tan (5 x) + sec^{2} (5 x) \cdot 5 sec (5 x))

Simplify

5 (sec (5 x) tan (5 x) \cdot 5 tan (5 x) + sec^{2} (5 x) \cdot 5 sec (5 x)) : 5 (5 tan^{2} (5 x) sec (5 x) + 5 sec^{3} (5 x))

= 5 (5 tan^{2} (5 x) sec (5 x) + 5 sec^{3} (5 x))

\int_{0}^{0.5} 8 y^{2} d y

\frac{5}{t ^{2}}

\int \frac{3}{9 x ^{2} + 6 x + 1} d x

\int \frac{x ^{2} + x + 1}{x ^{2} + 1} d x

\frac{3000 - 10 x ^{2} + 1}{3 x ^{3}}

What is the derivative of 5sec(5xtan(5x)) ?
The derivative of 5sec(5xtan(5x)) is 5(5tan^2(5x)sec(5x)+5sec^3(5x))
What is the first derivative of 5sec(5xtan(5x)) ?
The first derivative of 5sec(5xtan(5x)) is 5(5tan^2(5x)sec(5x)+5sec^3(5x))