What is the derivative of 3/t ?

The derivative of 3/t is -3/(t^2)

What is the first derivative of 3/t ?

The first derivative of 3/t is -3/(t^2)

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derivative of

\frac{3}{t}

- \frac{3}{t ^{2}}

Solution steps

\frac{d}{d t} (\frac{3}{t})

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= 3 \frac{d}{d t} (\frac{1}{t})

Apply exponent rule:

\frac{1}{a} = a^{- 1}

= 3 \frac{d}{d t} (t^{- 1})

Apply the Power Rule:

\frac{d}{d x} (x^{a}) = a \cdot x^{a - 1}

= 3 (- 1 \cdot t^{- 1 - 1})

Simplify

3 (- 1 \cdot t^{- 1 - 1}) : - \frac{3}{t ^{2}}

= - \frac{3}{t ^{2}}

\int 2 x (x^{2} + 2)^{3} d x

n = 1 \sum \infty \frac{1}{n ^{2} + 9}

\frac{d}{d x} (- \frac{18}{x ^{3}})

f (x) = \frac{1}{x - 2}, at x = 4

(\frac{19}{2}, - \frac{5}{3}), (- \frac{3}{2}, - \frac{7}{24})